Addition product is formed by anti-Markownikoff's rule.
2.
The negative part of the addendum ( the molecule to be added ) adds on to the carbon atom of the double bond containing the least number of hydrogen atoms. This rule is known as
No explanation is given for this question. Let's discuss the answer together.
3.
Classify the following compounds as primary, secondary and tertiary halides.
(i) 1-Bromobut-2-ene
(ii) 4-Bromopent-2-ene
(iii) 2-Bromo-2-methylpropane
A.
(i) - secondary, (ii) - tertiary, (iii) - primary
B.
(i) - secondary, (ii) - primary, (iii) - tertiary
C.
(i) - primary, (ii) - tertiary, (iii) - secondary
D.
(i) - primary, (ii) - secondary, (iii) - tertiary
$$\eqalign{
& RX + AgCN \to \mathop {RNC}\limits_{\left( A \right)} + AgX \cr
& RX + KCN \to \mathop {RCN}\limits_{\left( B \right)} + KX \cr} $$
Both $$C$$ and $$N$$ can donate electron pairs. Since $$KCN$$ is predominantly ionic and $$C - C$$ bond is more stable than $$C - N$$ bond in case of $$KCN,$$ attack takes place through carbon atom.
$$AgCN$$ is predominantly covalent hence only nitrogen pair is available for bonding resulting in formation of isocyanide.
5.
\[\xrightarrow[280\,K]{NaN{{O}_{2}}+HCl}K\xrightarrow{KI}Y\]
$$X$$ and $$Y$$ in the reaction are
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7.
In the following reaction sequence :
\[\underset{\left( {{C}_{3}}{{H}_{6}}C{{l}_{2}} \right)}{\mathop{I}}\,\xrightarrow{KOH\left( aq \right)}II\xrightarrow[\left( ii \right)\,{{H}_{2}}O/{{H}^{+}}]{\left( i \right)\,C{{H}_{3}}MgBr}III\xrightarrow{Anhy.ZnC{{l}_{2}}+Conc.HCl}\text{given}\,\text{turbidity immediately}\]
The compound $$I$$ is :
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9.
Arrange the following compounds in order of increasing dipole moment :
(I) Toluene
(II) $$m$$ - dichlorobenzene
(III) $$o$$ - dichlorobenzene
(IV) $$p$$ - dichlorobenzene
In $$p$$ - dichlorobenzene, the two equal dipoles are in opposite direction, hence the molecule has zero dipole moment. In $$o$$ - and $$m$$ - dichlorobenzenes, the two dipoles are at $${60^ \circ }$$ and $${120^ \circ }$$ apart respectively, and thus according to parallelogram law of forces, the dipole moment of $$o$$ - dichlorobenzene is much higher than that of $$m$$ - isomer. Lastly, toluene with a $$ + I$$ group possesses little dipole moment. Thus the overall order is
10.
A primary alkyl halide would prefer to undergo __________.